-2x^2-15x+27=0

Solution for -2x^2-15x+27=0 equation:

-2x^2-15x+27=0

a = -2; b = -15; c = +27;
Δ = b2-4ac
Δ = -152-4·(-2)·27
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-21}{2*-2}=\frac{-6}{-4}
=1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+21}{2*-2}=\frac{36}{-4}
=-9
$